(c-2)(c^2+4c-3)=

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Solution for (c-2)(c^2+4c-3)= equation:


Simplifying
(c + -2)(c2 + 4c + -3) = 0

Reorder the terms:
(-2 + c)(c2 + 4c + -3) = 0

Reorder the terms:
(-2 + c)(-3 + 4c + c2) = 0

Multiply (-2 + c) * (-3 + 4c + c2)
(-2(-3 + 4c + c2) + c(-3 + 4c + c2)) = 0
((-3 * -2 + 4c * -2 + c2 * -2) + c(-3 + 4c + c2)) = 0
((6 + -8c + -2c2) + c(-3 + 4c + c2)) = 0
(6 + -8c + -2c2 + (-3 * c + 4c * c + c2 * c)) = 0
(6 + -8c + -2c2 + (-3c + 4c2 + c3)) = 0

Reorder the terms:
(6 + -8c + -3c + -2c2 + 4c2 + c3) = 0

Combine like terms: -8c + -3c = -11c
(6 + -11c + -2c2 + 4c2 + c3) = 0

Combine like terms: -2c2 + 4c2 = 2c2
(6 + -11c + 2c2 + c3) = 0

Solving
6 + -11c + 2c2 + c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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